b^2+16b-57=0

Solution for b^2+16b-57=0 equation:

Simplifying
b2 + 16b + -57 = 0

Reorder the terms:
-57 + 16b + b2 = 0

Solving
-57 + 16b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-19 + -1b)(3 + -1b) = 0

Subproblem 1
Set the factor '(-19 + -1b)' equal to zero and attempt to solve:

Simplifying
-19 + -1b = 0

Solving
-19 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '19' to each side of the equation.
-19 + 19 + -1b = 0 + 19

Combine like terms: -19 + 19 = 0
0 + -1b = 0 + 19
-1b = 0 + 19

Combine like terms: 0 + 19 = 19
-1b = 19

Divide each side by '-1'.
b = -19

Simplifying
b = -19
Subproblem 2
Set the factor '(3 + -1b)' equal to zero and attempt to solve:

Simplifying
3 + -1b = 0

Solving
3 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1b = 0 + -3
-1b = 0 + -3

Combine like terms: 0 + -3 = -3
-1b = -3

Divide each side by '-1'.
b = 3

Simplifying
b = 3
Solution
b = {-19, 3}